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The suspended weight on the pulley creates a moment that acts around the shaft axis. A shear force V, developed in the shear key, keeps the pulley attached to the shaft. This force develops shear stress in the key at the radial distance where the pulley and shaft touch.
Divide this force V by the shear key area subjected to stress. (Note: Visualize the surface that would be exposed if V was large enough to break the shear key.)
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In total, you have answered {{calculate_results()[2]}} of the {{calculate_results()[3]}} problems correctly.
You have correctly answered {{calculate_results()[0]}} of {{calculate_results()[1]}} problems in this series.
In total, you have answered {{calculate_results()[2]}} of the {{calculate_results()[3]}} problems correctly.