Constructing the shear diagram
Considering the segment
from x = 4 m to x = 6 m
area under load
diagram = 0.00 kN
concentrated
forces = 0.00 kN
total shear force
change = 0.00 kN
at x = 4 m, V = +15.60 kN
total shear force
change = 0.00 kN
at x = 6 m, V = +15.60 kN