Now that we have calculated the necessary section properties, we can compute the normal and shear stresses acting at $B$, $\mathrm{3} \mathrm{in}\mathrm{.}$ above the neutral axis (the $z$ axis for this configuration).

Transverse
shear stress   $$\begin{gathered} {\tau }_{xy}=\frac{VQ}{It} \\ =-\frac{(60 kip)(48.0469 i{n}^3.)}{(560.03125 in{.}^4)(0.375 in.)}=13.73 ksi \end{gathered}$$