MecMovies 4.0 : M5.3: Deformation of a Compound Axial Member

The figure shows a compound axial member consisting of a larger cylindrical segment A B which is marked 1 having a length of 1800 millimeters flanged to another cylindrical segment B C which is marked 2 having a length of 800 millimeters. Segment 1 is fixed to a wall at the point A. The x axis is taken along the common axis of the two cylindrical members and the y axis is taken perpendicular to the x axis along the wall. The tension load at the free end of segment 2 is P which equals 50 kilo newtons oriented in the positive x direction.

For the compound axial member considered here, the internal force $F$ is the same in both segments. However, $A$ and $E$ are different in segments $(1)$ and $(2)$ .

To compute the deflection of $C$ relative to $A$ , the elongation in each segment must be first considered individually. Then, the results can be summed according to:

$δ = \sum_{} {(\frac{FL}{AE})}_{i}$