MecMovies 4.0 : M5.3: Deformation of a Compound Axial Member

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Note: Assume a positive internal force (i.e., tension).

The figure shows a compound axial member consisting of a larger cylindrical segment A B which is marked 1 having a length of 1800 millimeters flanged to another cylindrical segment B C which is marked 2 having a length of 800 millimeters. Segment 1 is fixed to a wall at the point A. The x axis is taken along the common axis of the two cylindrical members and the y axis is taken perpendicular to the x axis along the wall. The tension load at the free end of segment 2 is P which equals 50 kilo newtons oriented in the positive x direction.

Cut a $FBD$ through segment $(2)$ .

Sum the forces acting in the $x$ direction.

$\sum_{} F_{x} = - F_{2} + 50 kN = 0 ∴ F_{2} = 50 kN$