$\sum _{}{\mathrm{M}}_{\mathrm{A}}={\mathrm{F}}_1(380 \mathrm{mm})+{\mathrm{F}}_2(760 \mathrm{mm})-\mathrm{P}(1,520 \mathrm{mm})=0$

A second equation involving the internal forces ${\mathrm{F}}_1$ and ${\mathrm{F}}_2$ must be developed to solve this problem. To do this, the geometry of the structure and its corresponding deformations will be considered.