MecMovies 4.0 : M5.7: Rigid Bar and Two Axial Members

scene 10 of 14

Calculate the normal stresses in bar $(1)$ :

$σ_{1} = \frac{F_{1}}{A_{1}} = \frac{(33.76 kN) (1, 000 N / kN)}{420 {mm}^{2}} = 80.4 MPa$

and bar $(2)$ :

$σ_{2} = \frac{F_{2}}{A_{2}} = \frac{(55.12 kN) (1, 000 N / kN)}{320 {mm}^{2}} = 172.3 MPa$