MecMovies 4.0 : M15.1: Combined Axial Force and Torsion

scene 2 of 9

The axial force $P$ will compress the shaft, creating a uniform normal stress given by:

$σ_{a x i a l} = \frac{P}{A}$

where

A

is the cross-sectional area of the shaft.

The torque $T$ will twist the shaft, creating a shear stress given by:

$τ = \frac{T c}{J}$

where $c$ is the outside radius of the shaft and $J$ is the polar moment of inertia.