MecMovies 4.0 : M1.1: Normal, Shear, and Bearing Stress

The figure shows a steel plate of width 60 millimeters and thickness 8 millimeters fixed to a gusset plate that is anchored to a column on the left by a pin. The diameter of the pin is 20 millimeters. An axial load of 70 kilo newtons acts on the plate and is directed to the right.

A $60 - mm$ wide by $8 - mm$ thick steel plate is connected to a gusset plate by a $20 - mm$ diameter pin. If a load of $P = 70 kN$ is applied, determine the normal, shear, and bearing stresses in this connection.

Shear stress in the pin

$A_{pin} = \frac{π (20 mm)^{2}}{4} = 314.16 {mm}^{2} τ_{pin} = \frac{(70 kN) (1, 000 N / kN)}{314.16 {mm}^{2}} = 222.82 MPa = 223 MPa$

Bearing stress in the plate

$σ_{b} = \frac{(70 kN) (1, 000 N / kN)}{(20 mm) (8 mm)} = 437.50 MPa = 438 MPa$

Finished