MecMovies 4.0 : M1.6: Shear Stress in Bolted Flanges

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The figure on the left shows a shaft with a flange at one end. The axis of the shaft is along the x axis. The torque at the end of the shaft has a magnitude T and is directed counterclockwise. The force on each of the bolt is F subscript bolt directed opposite to the torque T. The figure on the right shows the front view of the flange. The bolt circle has a diameter of 250 millimeters.

The diameter of each bolt is $22 mm$ ; therefore, the cross-sectional area of each bolt is:

$A_{bolt} = \frac{π}{4} {(22 mm)}^{2} = 380.133 {mm}^{2}$

The average shear stress in each bolt can now be calculated:

$τ = \frac{F_{bolt}}{A_{bolt}} = \frac{(20 kN) (1, 000 N / kN)}{380.133 {mm}^{2}} = 52.6 MPa$