2. The relationship between the internal force and the deformation of an axial member is given by:

$\mathrm{\delta }=\frac{\mathrm{FL}}{\mathrm{AE}}$

   Using this relationship, the deformations for both members $\left(1\right)$ and $\left(2\right)$ will be computed.

${\mathrm{\delta }}_1=\frac{{\mathrm{F}}_1{\mathrm{L}}_1}{{\mathrm{A}}_1{\mathrm{E}}_1} {\mathrm{\delta }}_2=\frac{{\mathrm{F}}_2{\mathrm{L}}_2}{{\mathrm{A}}_2{\mathrm{E}}_2}$