The figure shows a column A B C with its central axis along the x axis. Joint A is at the base. Joint B is 5 meters above joint A and joint C is 4.2 meters above joint C. The forces on either side of joint B have magnitude of 175 kilo newtons and are directed downwards. The forces on either side of joint C have magnitude of 125 kilo newtons and are directed downwards. Points 1 and 2 are marked on the column below joint C and joint B respectively.

Using the internal forces determined for members (1) and (2) along with the column area (A=7,500 mm2) and elastic modulus (E=200 GPa), compute the deformations in each member.

Note: Make sure that the equation is in consistent units before making the calculation.