and the deformation in member $\left(2\right)$:

$$\begin{gathered} {\mathrm{\delta }}_2=\frac{{\mathrm{F}}_2{\mathrm{L}}_2}{{\mathrm{A}}_2{\mathrm{E}}_2} \\ =\frac{(-600,000 \mathrm{N})(5,000 \mathrm{mm})}{(7,500 {\mathrm{mm}}^2)(200,000 \mathrm{N}/{\mathrm{mm}}^2)} \\ =-2.00 \mathrm{mm} \end{gathered}$$

Note that both deformations are negative, indicating that they contract (i.e., get shorter) as a result of the internal compression forces.