The figure shows the deflections suffered by the rigid bar A C B. Joints A and C are separated by 0.7 meters and joints C and B are separated by 0.3 meters. The deflection at joint A is v subscript A which equals 2.40 millimeters. The deflection at joint C is v subscript C. The deflection at joint B is v subscript B which equals 3.60 millimeters. A horizontal line is drawn from A and a diagonal line is drawn passing through A, C and B. Point C is offset from the horizontal by delta and point B is offset from the horizontal by 1.2 millimeters.

Use the principle of similar triangles to find the rigid bar deflection at C.

0.7 m=1.20 mm1 m      =0.84 mm

vC=vA+=2.40 mm+0.84 mm=3.24 mm