The rotation of gear $\mathrm{D}$ with respect to flange $\mathrm{A}$ is thus:

$$\begin{gathered} {\mathrm{\varphi }}_2={\mathrm{\varphi }}_{\mathrm{D}}-{\mathrm{\varphi }}_{\mathrm{C}} \\ \therefore {\mathrm{\varphi }}_{\mathrm{D}}={\mathrm{\varphi }}_{\mathrm{C}}+{\mathrm{\varphi }}_2 \\ =0.016908 \mathrm{rad}+0.052590 \mathrm{rad} \\ =0.069498 \mathrm{rad}=\mathbf{0}\mathbf{.}\mathbf{0695}\mathbf{ }\mathbf{rad} \end{gathered}$$