MecMovies 4.0 : M15.7: Combined Loadings

Write the equilibrium equations for the post and solve for $F$ , $V$ , and $M$ :

$\overset{+}{\to} \underset{}{\sum F_{x} = V} + 8.66 k N = 0$

∴ V = - 8.66 k N

$+ ↑ \sum_{} F_{y} = F - 5.00 k N = 0$

∴ F = 5.00 k N

$⤹ + \sum_{} M_{b a s e} = M - (8.66 k N) (1, 200 m m) - (5.00 k N) (500 m m) = 0$

∴ M = 12, 892 k N - m m

Notice that the moment

M

is always calculated with respect to the centroid of the cross section, not to the particular location of point

B