$$\begin{gathered} =\frac{(11.077 \mathrm{kN})(1,000 \mathrm{N}/\mathrm{kN})}{70.0 {\mathrm{mm}}^2} \\ =\mathbf{158}\mathbf{.}\mathbf{2}\mathbf{ }\mathbf{MPa} \mathbf{\left(}\mathbf{tension}\mathbf{\right)} \\ { \\ }_{ \\ } \end{gathered}$$

and in rod $$\begin{gathered} \left(2\right) \\ { \\ }_{ \\ } \end{gathered}$$:

$$\begin{gathered} {\mathrm{\sigma }}_2=\frac{{\mathrm{F}}_2}{{\mathrm{A}}_2} \\ =\frac{(-79.012 \mathrm{kN})(1,000 \mathrm{N}/\mathrm{kN})}{625.0 {\mathrm{mm}}^2} \\ =\mathbf{126}\mathbf{.}\mathbf{4}\mathbf{ }\mathbf{MPa} \mathbf{\left(}\mathbf{compression}\mathbf{\right)} \\ { \\ }_{ \\ } \end{gathered}$$