MecMovies 4.0 : M6.7: Multiple Torques

scene 5 of 9

Free-Body diagram of the shaft A B C which cuts through A B shows the torques 600 Newton meter, 200 Newton meter acting on B and C, and a positive internal torque T subscript 1 acts on A B towards A. The length of A B is 100 millimeters, B C is 300 millimeters. The internal torque at A B is 400 Newton meter. A positive internal torque T subscript 2 acts on B C towards B.

Next, find the torque in shaft segment $(2)$ with a $FBD$ that cuts through segment $(2)$ and includes the free end of the shaft.

Sum the torques acting on the $FBD$ :

$\sum_{} M = - T_{2} - 200 N - m = 0 ∴ T_{2} = - 200 N - m$