MecMovies 4.0 : M15.2: Principal Stresses in a Tee Beam

scene 9 of 14

The transverse shear stress at $D$ located $2.96 i n .$ below the neutral axis is:

$τ = \frac{V Q}{I t} = \frac{(10 k i p s) (7.936 i n .^{3})}{(70.55 i n .^{4}) (0.40 i n .)} = 2.81 k s i$

The shear stress in the beam is computed from the transverse shear stress formula:

$τ = \frac{V Q}{I t}$

where $V =$ internal shear force, $Q =$ moment of area about the neutral axis, $I =$ moment of inertia about the centroidal axis, and $t =$ width of the beam at the point of interest.