Based on the allowable stress and area given for each axial member, the allowable axial forces can be computed:

$$\begin{gathered} {\mathrm{F}}_{1,\mathrm{allow}}={\mathrm{\sigma }}_1 {\mathrm{A}}_1 \\ =(180 \mathrm{MPa})(3,080 {\mathrm{mm}}^2) \\ =554,400 \mathrm{N} \\ =554.4 \mathrm{kN} \end{gathered}$$

$$\begin{gathered} {\mathrm{F}}_{2,\mathrm{allow}}={\mathrm{\sigma }}_2 {\mathrm{A}}_2 \\ =(75 \mathrm{MPa})(4,650 {\mathrm{mm}}^2) \\ =348,750 \mathrm{N} \\ =348.75 \mathrm{kN} \end{gathered}$$