Draw a free-body diagram of joint $\mathrm{B}$ and write the two equilibrium equations, $\sum _{}^{}{\mathrm{F}}_{\mathrm{x}}=0$ and $\sum _{}^{}{\mathrm{F}}_{\mathrm{y}}=0$:

$\sum _{}^{}{\mathrm{F}}_{\mathrm{x}}={\mathrm{F}}_{1 }\cos (49.3^{\circ })+{\mathrm{F}}_2 \cos (24.9^{\circ })=0$

$\sum _{}^{}{\mathrm{F}}_{\mathrm{y}}={\mathrm{F}}_{1 }\sin (49.3^{\circ })-{\mathrm{F}}_2 \sin (24.9^{\circ })-\mathrm{P}=0$