Member (2) has been shown to be the factor that limits the load-carrying capacity of the structure. To compute the magnitude of load $\mathrm{P}$, set:

${\mathrm{F}}_2=-348.75 \mathrm{kN}$

and once again solve the two equilibrium equations simultaneously, this time for unknown forces ${\mathrm{F}}_1$ and $\mathrm{P}$.

Note: While the magnitude of ${\mathrm{F}}_2$ equals its allowable force, the negative sign is attached because the previous calculation showed that member (2) acts in compression.