Multiply the three previous results by this ratio to obtain the final forces.

$$\begin{gathered} {\mathrm{F}}_1=(554.4 \mathrm{kN})(0.87494) \\ =485.07 \mathrm{kN} \end{gathered}$$

$$\begin{gathered} {\mathrm{F}}_2=(-398.6 \mathrm{kN})(0.87494) \\ =-348.75 \mathrm{kN} \end{gathered}$$

$$\begin{gathered} \mathrm{P} =(588.1 \mathrm{kN})(0.87494) \\ =514.55 \mathrm{kN} \end{gathered}$$