The maximum allowable load P is determined such that neither F1 nor F2 exceeds their respective allowable forces.

For member (2), P must not produce more than 348.75 kN of axial force in member (2). Note that force magnitudes are considered here. Consequently, only the absolute value is considered in the inequality.

P-1.47557 F2  -1.47557(348.75 kN)  514.61 kN

The figure shows a diagonal member labeled 1 and a horizontal member labeled fixed to a column on the right at the points A on top and C below. The diagonal member runs between 
points A and B and the horizontal member runs between the points B and C. Joint B is at a distance of 4.3 meters to the left 
of A and 5 meters below A. Joint C is at a distance of 7 meters directly below A. The load at joint B is labeled P and it is 
directed downwards.