Equate the shear force acting in bolts $\mathrm{A}$ and $\mathrm{B}$ (i.e., the force ${\mathrm{F}}_1$) to the allowable bolt shear force and solve for $\mathrm{w}$.
Since only the magnitude of $\mathrm{w}$ is desired, consider the absolute value of ${\mathrm{F}}_1$.

$\left|(-2.2595 \mathrm{m})(\mathrm{w} \mathrm{kN/}\mathrm{m})\right|=56.3 \mathrm{kN} \therefore \mathrm{w}=24.92 \mathrm{kN/}\mathrm{m}$