MecMovies 4.0 : M4.3: Load Capacity of Beam-strut Structure

The figure shows the free body diagram of the beam. The reaction forces at C are C subscript x and C subscript y directed horizontally to the right and vertically upwards respectively. The load on the beam is 3.6 meters times w kilo newton per meter and it acts at a distance of 1.8 meters from C. The force along the support rod directed away from the point B is F subscript 1 at an angle of 35 degrees with the horizontal.

Previously, it was shown that the resultant force acting on bolt $C$ could be expressed as:

$|C| = \sqrt{{(C_{x})}^{2} + {(C_{y})}^{2}} = (2.9554 m) (w kN/ m)$

Like bolts $A$ and $B$ , bolt $C$ also has a diameter of $16 mm$ . Therefore, the allowable shear force (denoted $V$ ) for bolt $C$ is also $56.3 kN$ .

Equate the shear force acting in bolt $C$ (i.e., the resultant force at $C$ ) to the allowable bolt shear force and solve for $w$ .

$(2.9554 m) (w kN/ m) = 56.3 kN ∴ w = 19.05 kN/ m$