The figure shows the free body diagram of the tube near the free end B. The load on top of the tube is P which equals 30 kilo newtons directed vertically downwards. The reaction force on member 2 is F subscript 2 directed vertically downwards. The reaction force at the base of the tube is F subscript 1 directed vertically downwards.

For an axial member, the relationship between its internal force and its deformation is given by:

δ=FLAE

where
δ = deformation,
F = internal force,
L = member length,
A = cross-sectional area, and
E = elastic modulus.