The figure shows the free body diagram of the tube near the free end B. The load on top of the tube is P which equals 30 kilo newtons directed vertically downwards. The reaction force on member 2 is F subscript 2 directed vertically downwards. The reaction force at the base of the tube is F subscript 1 directed vertically downwards.

Substitute the expression for F1 into the equilibrium equation:

Fy=-F1-F2-30 kN=0        -(0.573 F2)-F2=30 kN        -1.573 F2=30 kN

F2=-19.07 kN        

Backsubstitute to find F1:

F1=0.573 F2   =0.573(-19.07 kN)        

F1=-10.93 kN