MecMovies 4.0 : M6.8: Maximum Torque Based on Twist Angle

scene 5 of 12

Cut a $FBD$ through shaft segment $(1)$ to determine internal torque $T_{1}$ :

$\sum_{} M_{x} = T_{C} - 20 N - m - T_{1} = 0 ∴ T_{1} = T_{C} - 20 N - m$

Cut a $FBD$ through shaft segment $(2)$ to determine internal torque $T_{2}$ :

$\sum_{} M_{x} = T_{C} - T_{2} = 0 ∴ T_{2} = T_{C}$