MecMovies 4.0 : M6.8: Maximum Torque Based on Twist Angle

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Diagram shows a shaft A B C containing two gears at B and C which is connected to a motor A where the torques of 20 Newton meter and T subscript c is applied on B and C and the distance A B is 1400 millimeter and B C is 1000 millimeter. A positive internal torque T subscript 1 acts on A B towards A. The x axis is taken along the axis of the gears.

Cut a $FBD$ through shaft segment $(1)$ to determine internal torque $T_{1}$ :

$\sum_{} M_{x} = T_{C} - 20 N - m - T_{1} = 0 ∴ T_{1} = T_{C} - 20 N - m$