MecMovies 4.0 : M6.6: Twisting of a Compound Torsion Member

scene 6 of 7

Diagram shows a shaft with brass segment A B of length 1800 millimeters which is connected to aluminum segment B C of length 800 millimeter using a flange at B and a torque T of 50 Newton meter is applied on C. The x axis is taken along the axis of the cylinders and the y axis is taken along the rigid support at A and perpendicular to the x axis. A positive internal torque T subscript 2 acts on B C towards B.

Note: Assume a positive internal torque.

Cut a $FBD$ through segment $(2)$ of the compound shaft.

Sum the moments acting around the $x$ axis to find $T_{2}$ .

$\sum_{} M_{x} = - T_{2} + 50 N - m = 0 ∴ T_{2} = 50 N - m$