Using the values computed for ${\mathrm{T}}_1$ and ${\mathrm{T}}_2$, calculate the shear stresses in each shaft:

${\mathrm{\tau }}_1=\frac{{\mathrm{T}}_1{\mathrm{c}}_1}{{\mathrm{J}}_1}=\frac{(424.63 \mathrm{N-m})(25 \mathrm{mm})(\mathrm{1,000} \mathrm{mm/m})}{\mathrm{362,265} {\mathrm{mm}}^4}=29.30 \mathrm{MPa}$

${\mathrm{\tau }}_2=\frac{{\mathrm{T}}_2{\mathrm{c}}_2}{{\mathrm{J}}_2}=\frac{(-575.37 \mathrm{N-m})(25 \mathrm{mm})(\mathrm{1,000} \mathrm{mm/m})}{\mathrm{613,592} {\mathrm{mm}}^4}=-23.44 \mathrm{MPa}$