MecMovies 4.0 : M6.23: Shafts With Specified Rotation Angle

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Diagram shows an aluminum shaft A B with a support at A, marked 1 of length 2,000 millimeters and a brass shaft B C with a support at C, marked 2 of length 800 millimeters with a flange in between at B. The shafts are centered on the x axis. A torque T is applied at B. An internal torque T subscript 1 is applied on the post towards A and an internal torque T subscript 2 is applied on the post towards C.

Draw a FBD around flange B.

Assume positive internal torques T₁ and T₂ in shafts (1) and (2).

The equilibrium equation obtained from this FBD is:

\sum_{} M_{x} = - T_{1} + T_{2} + T = 0

∴ T = T_{1} - T_{2}