MecMovies 4.0 : M6.23: Shafts With Specified Rotation Angle

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For stainless steel shaft (1):

L_{1} = 2,000 mm

G_{1} = 86 GPa = 86,000 {N/mm}^{2}

J_{1} = 2,207,951 {mm}^{4}

Rearrange the torque-twist relationship for shaft (1) to solve for T₁:

T_{1} = ϕ_{1} \frac{J_{1} G_{1}}{L_{1}}

= (3 ˚) (\frac{π rad}{180 ˚}) \times \frac{(2,207,951 {mm}^{4}) (86,000 {N/mm}^{2})}{2,000 mm}

= 4,971,146 N-m = 4.97 kN-m