Diagram shows an aluminum shaft A B with a support at A, marked 1 of length 2,000 millimeters and a brass shaft B C with a support at C, marked 2 of length 800 millimeters with a flange in between at B. The shafts are centered on the x axis. A torque T is applied at B.

The internal torques in the stainless steel and bronze shafts are now known:

T1=4.97 kN-m
T2=-7.73 kN-m

Substitute these values into the equilibrium equation to obtain the concentrated torque T:

T=T1-T2
=4.97 kN-m -(-7.73 kN-m)
=12.70 kN-m
Note: Make sure that you have the proper signs on both torques. This is a very easy error to make, and one that is hard to track down.