Diagram shows a shaft A B with aluminum segment marked 1 of length 400 millimeters inside which is a brass shaft marked 2. Both the shafts are centered on the central axis x. A torque T is applied at B.

Before proceeding, we must compute section properties for shafts (1) and (2).

For shaft (1):

J1=π32(D14-d14)   =π32(50 mm)4-(24 mm)4  =308,102 mm4

and

c1=50 mm2=25 mm

For shaft (2):

J2=π32(D14-d14)   =π32(42 mm)4-(30 mm)4  =225,968 mm4

and

c2=42 mm2=21 mm